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NEW QUESTION: 1
A. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNION ALLSELECT CustNoFROM tblLoanAcct) R
B. SELECT COUNT(DISTINCT L.CustNo)FROM tblDepositAcct DRIGHT JOIN tblLoanAcct L ON D.CustNo L.CustNoWHERE D.CustNo IS NULL
C. SELECT COUNT(*)FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNo
D. SELECT COUNT(*)FROM (SELECT AcctNoFROM tblDepositAcctINTERSECTSELECT AcctNoFROM tblLoanAcct) R
E. SELECT COUNT (DISTINCT COALESCE(D.CustNo, L.CustNo))FROM tblDepositAcct DFULL JOIN tblLoanAcct L ON D.CustNo = L.CustNoWHERE D.CustNo IS NULL OR L.CustNo IS NULL
F. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctUNIONSELECT CustNoFROM tblLoanAcct) R
G. SELECT COUNT(*)FROM (SELECT CustNoFROM tblDepositAcctEXCEPTSELECT CustNoFROM tblLoanAcct) R
H. SELECT COUNT (DISTINCT D.CustNo)FROM tblDepositAcct D, tblLoanAcct LWHERE D.CustNo L.CustNo
Answer: D
Explanation:
The SQL INTERSECT operator is used to return the results of 2 or more SELECT statements. However, it only returns the rows selected by all queries or data sets. If a record exists in one query and not in the other, it will be omitted from the INTERSECT results.
References: https://www.techonthenet.com/sql/intersect.php
NEW QUESTION: 2
Which four pieces of information are stored for each prefix in the LFIB? (Choose four.)
A. next-hop IP address
B. incoming interface
C. outgoing label
D. local label
E. Layer 2 header rewrite information
F. outgoing interface
Answer: A,C,D,F
Explanation:
Explanation/Reference:
Explanation:
NEW QUESTION: 3
Lower than normal throughput is being experienced between two routers. What can be seen on the router interface that may be contributing to this issue?
A. drops from malformed packets
B. discards due to router access control lists (ACLs)
C. routing changes
D. when the traffic change occurred
Answer: A
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