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NEW QUESTION: 1
You have an Azure Storage account and an Azure SQL data warehouse by using Azure Data Factory. The solution must meet the following requirements:
* Ensure that the data remains in the UK South region at all times.
* Minimize administrative effort.
Which type of integration runtime should you use?
A. Azure-SSIS integration runtime
B. Azure integration runtime
C. Self-hosted integration runtime
Answer: B
Explanation:
Explanation
References:
https://docs.microsoft.com/en-us/azure/data-factory/concepts-integration-runtime
NEW QUESTION: 2
Jane, the GL accountant, says that she had heard about the budget upload functionality of Oracle General Ledger and had been eager to test it. However, she was unable to test it in the Conference Room Pilot (CRP) instance. What would be your explanation?
A. The budget status may be frozen.
B. Budget journals are required at the ledger level.
C. The GL account code combination is invalid.
D. The GL period is closed.
E. The budget dates in the budget organization have a different date range.
Answer: B
NEW QUESTION: 3
Which statement about the feasibility condition in EIGRP is true?
A. The EIGRP peer that advertises the prefix to the router is closer to the destination than the router.
B. The prefix is reachable via an EIGRP peer that is in the routing domain of the router.
C. The EIGRP peer that advertises the prefix to the router has multiple paths to the destination.
D. The EIGRP peer that advertises the prefix cannot be used as a next hop to reach the destination.
Answer: A
Explanation:
The advertised metric from an EIGRP neighbor (peer) to the local router is called Advertised Distance (or reported distance) while the metric from the local router to that network is called Feasible Distance. For example, R1 advertises network 10.10.10.0/24 with a metric of 20 to R2. For R2, this is the advertised distance. R2 calculates the feasible distance by adding the metric from the advertised router (R1) to itself. So in this case the feasible distance to network 10.10.10.0/24 is 20 + 50 = 70.
Before a router can be considered a feasible successor, it must pass the feasibility condition rule.
In short, the feasibility condition says that if we learn about a prefix from a neighbor, the advertised distance from that neighbor to the destination must be lower than our feasible distance to that same destination.
Therefore we see the Advertised Distance always smaller than the Feasible Distance to satisfy the feasibility condition.
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