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NEW QUESTION: 1
What is one way that HPE helps you to make every engagement a success?
A. HPE focuses on software innovation and connects you with third-party vendors to deliver services.
B. HPE solutions are built as turn-key infrastructure that convinces customers they do not need to move to the cloud.
C. HPE offers customers unique financial incentives for rapidly moving to pure HPE public cloud services.
D. HPE solutions are designed to help customers at any phase in a transformation to a hybrid infrastructure.
Answer: D
NEW QUESTION: 2
Universal container would like to use a chatter group for their mergers andacquisitions team to collaborate on potential new projects. This project should notbe visible for non-members to see or join,and can be accessed by invites only.
A. Public group
B. Member group
C. Unlisted group
D. Private group
Answer: C
NEW QUESTION: 3
Hinweis: Diese Frage ist Teil einer Reihe von Fragen, die dasselbe Szenario darstellen. Jede Frage in der Reihe enthält eine eindeutige Lösung. Stellen Sie fest, ob die Lösung die angegebenen Ziele erfüllt.
Sie haben eine Tabelle mit einem Clustered-Index und einem Nonclustered-Index. Die Indizes verwenden andere Spalten aus der Tabelle. Sie haben eine Abfrage mit dem Namen Query1, die den nicht gruppierten Index verwendet.
Benutzer geben an, dass es lange dauert, bis Query1 Ergebnisse ausgibt. Sie führen Query1 aus und überprüfen die folgenden Statistiken für eine Indexsuchoperation:
Sie müssen das Leistungsproblem beheben.
Lösung: Sie aktualisieren die Statistiken für den nicht gruppierten Index.
Entspricht die Lösung dem Ziel?
A. Nein
B. Ja
Answer: B
Explanation:
Explanation
We see Actual Number of Row is 3571454, while Estimated Number of Rows is 0.
This indicates that the statistics are old, and need to be updated.
NEW QUESTION: 4
そのコースを与えられます。txtはアクセス可能で、含んでいる内容:
Course : : Java
and given the code fragment:
public static void main (String[ ] args) {
int i;
char c;
try (FileInputStream fis = new FileInputStream ("course.txt");
InputStreamReader isr = new InputStreamReader(fis);) {
while (isr.ready()) { //line n1
isr.skip(2);
i = isr.read ();
c = (char) i;
System.out.print(c);
}
} catch (Exception e) {
e.printStackTrace();
}
}
結果は何ですか？
A. プログラムは、何も印刷しません。
B. ur :: va
C. ueJa
D. 編集エラーは、線n1で発生します。
Answer: C
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