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NEW QUESTION: 1
CORRECT TEXT
Answer:
Explanation:
Router>enable Router#config terminal Router(config)#hostname Apopka 2) Enable-secret password (cisco10): Apopka(config)#enable secret cisco10 3) Set the console password to RouterPass: Apopka(config)#line console 0 Apopka(config-line)#password RouterPass Apopka(config-line)#login Apopka(config-line)#exit 4) Set the Telnet password to scan90: Apopka(config)#line vty 0 4 Apopka(config-line)#password scan90 Apopka(config-line)#login Apopka(config-line)#exit 5) Configure Ethernet interface (on the right) of router Apopka: The subnet mask of the Ethernet network 209.165.201.0 is 27. From this subnet mask, we can find out the increment by converting it into binary form, that is /27 = 1111 1111.1111 1111.1111 1111.1110 0000. Pay more attention to the last bit 1 because it tells us the increment, using the formula: Increment = 2place of the last bit 1 (starts counting from 0,from right to left), in this case increment = 25 = 32. Therefore: Increment: 32 Network address: 209.165.201.0 Broadcast address: 209.165.201.31 (because 209.165.201.32 is the second subnetwork, so the previous IP - 209.165.201.31 - is the broadcast address of the first subnet). -> The second assignable host address of this subnetwork is 209.165.201.2/27 Assign the second assignable host address to Fa0/0 interface of Apopka router: Apopka(config)#interface Fa0/0 Apopka(config-if)#ip address 209.165.201.2 255.255.255.224 Apopka(config-if)#no shutdown Apopka(config-if)#exit 6) Configure Serial interface (on the left) of router Apopka: Using the same method to find out the increment of the Serial network: Serial network 192.0.2.128/28: Increment: 16 (/28 = 1111 1111.1111 1111.1111 1111.1111 0000) Network address: 192.0.2.128 (because 8 * 16 = 128 so 192.0.2.128 is also the network address of this subnet) Broadcast address: 192.0.2.143 -> The last assignable host address in this subnet is 192.0.2.142/28. Assign the last assignable host address to S0/0/0 interface of Apopka router: Apopka(config)#interface S0/0/0 (or use interface S0/0 if not successful) Apopka(config-if)#ip address 192.0.2.142 255.255.255.240 Apopka(config-if)#no shutdown Apopka(config-if)#exit 7) Configure RIP v2 routing protocol: Apopka(config)#router rip Apopka(config-router)#version 2 Apopka(config-router)#network 209.165.201.0 Apopka(config-router)#network 192.0.2.128
Apopka(config-router)#end
Save the configuration:
Apopka#copy running-config startup-config
Finally, you should use the ping command to verify all are working properly!
NEW QUESTION: 2
What is the function of this command?
switch(config-if)# switchport port-security mac-address sticky
A. It allows the switch to permanently store the secured MAC addresses in the MAC address table (CAM table).
B. It allows the switch to restrict the MAC addresses on the switch port, based on the static MAC addresses configured
in the startup configuration.
C. It allows the administrator to manually configure the secured MAC addresses on the switch port.
D. It allows the switch to perform sticky learning, in which the dynamically learned MAC addresses are copied from
the MAC address table (CAM table) to the startup configuration.
E. It allows the switch to dynamically learn the MAC addresses on the switch port, and the MAC addresses will be
added to the running configuration
Answer: E
NEW QUESTION: 3
HOTSPOT
Refer to Exhibit:
Container1 hosts a website on port 8080.
You create a port mapping between port 8080 on Container1 and port 80 on Server1.
Which URL can you use to access the website from Server1, Server2, and Container2? To answer, select the appropriate options in the answer area.
Answer:
Explanation:
NEW QUESTION: 4
New servers were purchased specifically for virtualization capabilities. However, the hypervisor of choice cannot find compatible processors on the new servers. Which of the following would a system administrator MOST likely need to configure to enable virtualization features for these systems?
A. BIOS
B. RAM
C. HBAs
D. IPMI
Answer: A
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